Use the one-to-one property of logarithms to solve.
$\begin{array}{l} \ln (80 - 6 x) = \ln (- 7 x) \\ x = ◻ \end{array}$

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Final Answer: $x = - 80$

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Step 1 ：Use the one-to-one property of logarithms to solve the equation $\ln (80 - 6 x) = \ln (- 7 x)$ .

Step 2 ：The one-to-one property of logarithms states that if $\ln a = \ln b$ , then $a = b$ . Therefore, we can set the arguments of the logarithms equal to each other and solve for $x$ .

Step 3 ：Setting $80 - 6 x$ equal to $- 7 x$ , we get the equation $80 - 6 x = - 7 x$ .

Step 4 ：Solving this equation, we find that $x = - 80$ .

Step 5 ：Final Answer: $x = - 80$

Use the one-to-one property of logarithms to solve.ln⁡(80−6x)=ln⁡(−7x)x=◻

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Use the one-to-one property of logarithms to solve.
$\begin{array}{l} \ln (80 - 6 x) = \ln (- 7 x) \\ x = ◻ \end{array}$