If 1500 dollars is invested in an account for 10 years. Find the value of the investment at the end of 10 years if the interest is:
(a) $6.6 \%$ compounded annually: $\$$
(b) $6.6 \%$ compounded semiannually: $\$$
(c) $6.6 \%$ compounded quarterly: $\$$
(d) $6.6 \%$ compounded monthly: $\$$
(e) $6.6 \%$ compounded daily (ignore leap years): $\$$

Round answers to the nearest cent.
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Step 1 ：\(A = P(1 + \frac{r}{n})^{nt}\)

Step 2 ：\(A = 1500(1 + \frac{0.066}{1})^{1*10}\)

Step 3 ：\(A = 1500 * 1.8197008586099825\)

Step 4 ：\(\boxed{A = \$2730.55}\)

Step 5 ：\(A = 1500(1 + \frac{0.066}{2})^{2*10}\)

Step 6 ：\(A = 1500 * 1.824567067879172\)

Step 7 ：\(\boxed{A = \$2736.85}\)

Step 8 ：\(A = 1500(1 + \frac{0.066}{4})^{4*10}\)

Step 9 ：\(A = 1500 * 1.827125820891125\)

Step 10 ：\(\boxed{A = \$2740.69}\)

Step 11 ：\(A = 1500(1 + \frac{0.066}{12})^{12*10}\)

Step 12 ：\(A = 1500 * 1.828476014536334\)

Step 13 ：\(\boxed{A = \$2742.71}\)

Step 14 ：\(A = 1500(1 + \frac{0.066}{365})^{365*10}\)

Step 15 ：\(A = 1500 * 1.8295065829545702\)

Step 16 ：\(\boxed{A = \$2744.26}\)