Given two vectors a→=3i^−2j^+k^ and b→=−i^+2j^−3k^, find the vector a→−b→.
The k component of a→−b→ is 1−(−3)=4
Step 1 :First, we subtract the components of vector b→ from the components of vector a→
Step 2 :The i component of a→−b→ is 3−(−1)=4
Step 3 :The j component of a→−b→ is −2−2=−4
Step 4 :The k component of a→−b→ is 1−(−3)=4