Approximate the mean for following GFDT.
\begin{tabular}{|c|c|}
\hline Data & Frequency \\
\hline $50-54$ & 1 \\
\hline $55-59$ & 2 \\
\hline $60-64$ & 8 \\
\hline $65-69$ & 10 \\
\hline $70-74$ & 17 \\
\hline $75-79$ & 14 \\
\hline $80-84$ & 9 \\
\hline $85-89$ & 4 \\
\hline $90-94$ & 1 \\
\hline
\end{tabular}
\[
\text { mean }=
\]

Report answer accurate to one decimal place.

Step 1 ：The data given is in the form of a grouped frequency distribution table. The mean of this data can be calculated by multiplying each data point (which is the midpoint of each group) by its corresponding frequency, summing these products, and then dividing by the total frequency.

Step 2 ：The midpoint of each group can be calculated by taking the average of the lower and upper bounds of each group. The data points and their frequencies are as follows: \((52, 1), (57, 2), (62, 8), (67, 10), (72, 17), (77, 14), (82, 9), (87, 4), (92, 1)\)

Step 3 ：The total frequency is \(66\)

Step 4 ：The sum of the product of each data point and its corresponding frequency is \(4812\)

Step 5 ：The mean can be calculated by dividing the sum of the products by the total frequency. This gives a mean of \(72.9090909090909\)

Step 6 ：Rounding to one decimal place, the mean of the grouped frequency distribution table is approximately \(\boxed{72.9}\)