Determine the area under the standard normal curve that lies between (a) $Z=-2.14$ and $Z=2.14$, (b) $Z=-2.51$ and $Z=0$, and $(c) Z=1.92$ and $Z=2.06$.

E Click the icon to view a table of areas under the normal curve.
(a) The area that lies between $Z=-2.14$ and $Z=2.14$ is $\square$.
(Round to four decimal places as needed.)
(b) The area that lies between $Z=-2.51$ and $Z=0$ is $\square$.
(Round to four decimal places as needed.)
(c) The area that lies between $Z=1.92$ and $Z=2.06$ is $\square$.
(Round to four decimal places as needed.)

Step 1 ：First, we need to find the area that lies between \(Z=-2.14\) and \(Z=2.14\). The area to the left of \(Z=2.14\) is 0.9838 and the area to the left of \(Z=-2.14\) is 0.0162. The area between these two Z-scores is the difference of these two areas, which is 0.9838 - 0.0162 = 0.9676.

Step 2 ：Next, we need to find the area that lies between \(Z=-2.51\) and \(Z=0\). The area to the left of \(Z=0\) is 0.5 and the area to the left of \(Z=-2.51\) is 0.0060. The area between these two Z-scores is the difference of these two areas, which is 0.5 - 0.0060 = 0.4940.

Step 3 ：Finally, we need to find the area that lies between \(Z=1.92\) and \(Z=2.06\). The area to the left of \(Z=2.06\) is 0.9803 and the area to the left of \(Z=1.92\) is 0.9726. The area between these two Z-scores is the difference of these two areas, which is 0.9803 - 0.9726 = 0.0077.

Step 4 ：So, the areas under the standard normal curve that lie between the given Z-scores are approximately \(\boxed{0.9676}\), \(\boxed{0.4940}\), and \(\boxed{0.0077}\), respectively.