Determine whether the given ordered pair is a solution of the system of equations.
\[
\begin{array}{r}
(2,6) ; \quad-6 x+y=-6 \\
8 x+y=10
\end{array}
\]

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Answer

\(\boxed{\text{Therefore, the ordered pair (2,6) is not a solution to the system of equations.}}\)

Steps

Step 1 ：Substitute the ordered pair (2,6) into the first equation -6x + y = -6, we get \(-6(2) + 6 = -12 + 6 = -6\).

Step 2 ：The ordered pair (2,6) satisfies the first equation.

Step 3 ：Substitute the ordered pair (2,6) into the second equation 8x + y = 10, we get \(8(2) + 6 = 16 + 6 = 22\).

Step 4 ：The ordered pair (2,6) does not satisfy the second equation because 22 is not equal to 10.

Step 5 ：\(\boxed{\text{Therefore, the ordered pair (2,6) is not a solution to the system of equations.}}\)