The manager at the local auto shop has found that the probability that a car brought into the shop requires an oil change is 0.71 , the probability that a car brought into the shop requires brake repair is 0.29 , and the probability that a car requires both an oil change and brake repair is 0.11 . For a car brought into the shop, determine the probability that the car will require an oil change or brake repair.
The probability that the car requires an oil change or brake repair is $\square$.
(Type an integer or a decimal.)
Final Answer: The probability that the car requires an oil change or brake repair is \(\boxed{0.89}\).
Step 1 :Define the probabilities: the probability that a car requires an oil change is 0.71, the probability that a car requires brake repair is 0.29, and the probability that a car requires both an oil change and brake repair is 0.11.
Step 2 :Calculate the probability of either event happening. This is done by adding the probability of an oil change and the probability of a brake repair, then subtracting the probability of both happening. This is because the event of both happening has been counted twice - once in the oil change probability and once in the brake repair probability.
Step 3 :Using the formula \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\), where \(P(A)\) is the probability of an oil change, \(P(B)\) is the probability of a brake repair, and \(P(A \cap B)\) is the probability of both an oil change and brake repair, we find that the probability of either event is \(0.71 + 0.29 - 0.11 = 0.89\).
Step 4 :Final Answer: The probability that the car requires an oil change or brake repair is \(\boxed{0.89}\).