Fifteen items or less: The number of customers in line at a supermarket express checkout counter is a random variable with the following probability distribution.
\begin{tabular}{c|cccccc}
$x$ & 0 & 1 & 2 & 3 & 4 & 5 \\
\hline$P(x)$ & 0.05 & 0.25 & 0.30 & 0.20 & 0.15 & 0.05
\end{tabular}
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Part: $0 / 4$
Part 1 of 4
(a) Find $P(5)$.
\[
P(5)=\square \sqrt{x}
\]
Answer
Therefore, the final answer is \(\boxed{0.05}\).
Step 1 ：The problem provides a probability distribution table for the number of customers in line at a supermarket express checkout counter. The probability of having 5 customers in line, denoted as \(P(5)\), is given directly in the table.
Step 2 ：From the table, we can see that \(P(5) = 0.05\).
Step 3 ：Therefore, the final answer is \(\boxed{0.05}\).
