Consider a population that grows according to the recursive rule $P_{n}=P_{n-1}+35$, with initial population $P_{0}=60$.

Then:
\[
\begin{array}{l}
P_{1}= \\
P_{2}=
\end{array}
\]

Step 1 ：Consider a population that grows according to the recursive rule \(P_{n}=P_{n-1}+35\), with initial population \(P_{0}=60\).

Step 2 ：The question is asking for the population at time 1 and time 2 given the recursive rule.

Step 3 ：To solve this, we can use the recursive rule to calculate \(P_{1}\) and \(P_{2}\).

Step 4 ：For \(P_{1}\), we substitute \(n=1\) into the recursive rule to get \(P_{1}=P_{0}+35\).

Step 5 ：For \(P_{2}\), we substitute \(n=2\) into the recursive rule to get \(P_{2}=P_{1}+35\).

Step 6 ：We know that \(P_{0}=60\), so we can substitute this into the equations to find \(P_{1}\) and \(P_{2}\).

Step 7 ：Let's calculate these values.

Step 8 ：Substituting \(P_{0}=60\) into the equation for \(P_{1}\), we get \(P_{1}=60+35=95\).

Step 9 ：Substituting \(P_{1}=95\) into the equation for \(P_{2}\), we get \(P_{2}=95+35=130\).

Step 10 ：Final Answer: \(\begin{array}{l} P_{1}= \boxed{95} \ P_{2}= \boxed{130} \end{array}\)