Solve the compound inequality and give your answer in interval notation
$$8x-4<-68\text{ OR }-5x-1\le 9$$

Step 1 ：Start with the first inequality, $8x-4<-68$.

Step 2 ：Add 4 to both sides to isolate the term with x: $8x-4+4<-68+4$, which simplifies to: $8x<-64$.

Step 3 ：Divide both sides by 8 to solve for x: $x<-64/8$, which simplifies to: $x<-8$.

Step 4 ：Now, solve the second inequality, $-5x-1\le 9$.

Step 5 ：Add 1 to both sides to isolate the term with x: $-5x-1+1\le 9+1$, which simplifies to: $-5x\le 10$.

Step 6 ：Divide both sides by -5 to solve for x. Remember, when we divide or multiply an inequality by a negative number, we must reverse the direction of the inequality: $x\ge 10/-5$, which simplifies to: $x\ge -2$.

Step 7 ：So, the solution to the compound inequality is $x<-8$ OR $x\ge -2$. In interval notation, this is written as $(-\infty ,-8)\cup [-2,\infty )$.

Step 8 ：$\boxed{{\displaystyle x<-8\text{ OR }x\ge -2}}$