Solve the compound inequality and give your answer in interval notation
\[
8 x-4< -68 \text { OR }-5 x-1 \leq 9
\]

Step 1 ：Start with the first inequality, \(8x - 4 < -68\).

Step 2 ：Add 4 to both sides to isolate the term with x: \(8x - 4 + 4 < -68 + 4\), which simplifies to: \(8x < -64\).

Step 3 ：Divide both sides by 8 to solve for x: \(x < -64/8\), which simplifies to: \(x < -8\).

Step 4 ：Now, solve the second inequality, \(-5x - 1 \leq 9\).

Step 5 ：Add 1 to both sides to isolate the term with x: \(-5x - 1 + 1 \leq 9 + 1\), which simplifies to: \(-5x \leq 10\).

Step 6 ：Divide both sides by -5 to solve for x. Remember, when we divide or multiply an inequality by a negative number, we must reverse the direction of the inequality: \(x \geq 10/-5\), which simplifies to: \(x \geq -2\).

Step 7 ：So, the solution to the compound inequality is \(x < -8\) OR \(x \geq -2\). In interval notation, this is written as \((-∞, -8) \cup [-2, ∞)\).

Step 8 ：\(\boxed{x < -8 \text{ OR } x \geq -2}\)