Find the volume of the solid formed by rotating the region enclosed by
\[
x=0, x=1, y=0, y=5+x^{8}
\]
about the $x$-axis.
\[
V=
\]
cubic units

Step 1 ：Use the disk method to find the volume of the solid formed by rotating the region enclosed by the given equations about the x-axis.

Step 2 ：The volume of the solid is given by the integral of the area of the disks from the lower bound of x to the upper bound of x.

Step 3 ：The area of each disk is given by the formula \(\pi r^2\), where r is the distance from the x-axis to the curve \(y=5+x^8\).

Step 4 ：Set up the integral with the limits of integration from 0 to 1 and the integrand as \(\pi (5+x^8)^2\).

Step 5 ：Solve the integral to find the volume.

Step 6 ：The volume is \(\frac{4004\pi}{153}\) cubic units.

Step 7 ：\(\boxed{\frac{4004\pi}{153}}\) cubic units