The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below.
\[
\begin{array}{llllllll}
68.43 & 79.44 & 68.97 & 84.95 & 79.09 & 85.46 & 101.97 & 99.13
\end{array}
\]

ت Click the icon to view the table of critical t-values.
(a) Determine a point estimate for the population mean travel tax.

A point estimate for the population mean travel tax is $\$ \square$.
(Round to two decimal places as needed.)

Step 1 ：The given data represents the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. The data is as follows: 68.43, 79.44, 68.97, 84.95, 79.09, 85.46, 101.97, 99.13.

Step 2 ：A point estimate for the population mean travel tax can be calculated by finding the mean of the given data. The mean is the sum of all the values divided by the number of values.

Step 3 ：The sum of the given data is \(68.43 + 79.44 + 68.97 + 84.95 + 79.09 + 85.46 + 101.97 + 99.13\).

Step 4 ：The number of values in the data is 8.

Step 5 ：So, the mean of the data is \(\frac{68.43 + 79.44 + 68.97 + 84.95 + 79.09 + 85.46 + 101.97 + 99.13}{8}\).

Step 6 ：After calculating the above expression, we find that the mean of the data is approximately 83.43.

Step 7 ：Therefore, a point estimate for the population mean travel tax is \(\boxed{83.43}\).