The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 286 square meters, find the dimensions.

The width is $◻$ meters.
The length is $◻$ meters.

Step 1 ：Given that the length of a rectangle is 4 meters less than twice the width, we can express this as $l=2w-4$.

Step 2 ：We are also given that the area of the rectangle is 286 square meters. The area of a rectangle is calculated by multiplying the length by the width, so we can express this as $lw=286$.

Step 3 ：We now have a system of two equations, which we can solve to find the values of $w$ and $l$.

Step 4 ：Solving this system of equations gives us two possible solutions: $(-11,-26)$ and $(13,22)$.

Step 5 ：However, the dimensions of a rectangle cannot be negative, so we discard the first solution and take the second solution as the correct one.

Step 6 ：This means the width of the rectangle is 13 meters and the length is 22 meters.

Step 7 ：Final Answer: The width is $\boxed{{\displaystyle 13}}$ meters. The length is $\boxed{{\displaystyle 22}}$ meters.