Perform the indicated operation.
Subtract $\left(4 x^{2}-4\right)$ from the sum of $\left(x^{2}-7 x+5\right)$ and $\left(3 x^{2}-5 x+1\right)$
The answer is

Step 1 ：First, let's find the sum of \(x^{2}-7 x+5\) and \(3 x^{2}-5 x+1\).

Step 2 ：To do this, we add the like terms together: \(x^{2} + 3x^{2} = 4x^{2}\), \(-7x - 5x = -12x\), and \(5 + 1 = 6\).

Step 3 ：So, the sum of \(x^{2}-7 x+5\) and \(3 x^{2}-5 x+1\) is \(4x^{2} - 12x + 6\).

Step 4 ：Next, we subtract \(4 x^{2}-4\) from this sum.

Step 5 ：Again, we subtract the like terms: \(4x^{2} - 4x^{2} = 0x^{2}\), \(-12x - 0 = -12x\), and \(6 - (-4) = 6 + 4 = 10\).

Step 6 ：So, the result of subtracting \(4 x^{2}-4\) from the sum of \(x^{2}-7 x+5\) and \(3 x^{2}-5 x+1\) is \(0x^{2} - 12x + 10\).

Step 7 ：Since \(0x^{2}\) is simply \(0\), we can simplify this to \(-12x + 10\).

Step 8 ：So, the final answer is \(\boxed{-12x + 10}\).