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Use a graphing calculator and the following scenario.
The population $P$ of a fish farm in $t$ years is modeled by the equation $P(t)=\frac{1200}{1+9 e^{-0.8 t}}$.

To the nearest whole number, what will the fish population be after 2 years?
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Answer

So, to the nearest whole number, the fish population after 2 years will be $\boxed{426}$

Steps

Step 1 ：Substitute $t=2$ into the equation to get $P(2)=\frac{1200}{1+9 e^{-0.8 * 2}}$

Step 2 ：Simplify the exponent to get $P(2)=\frac{1200}{1+9 e^{-1.6}}$

Step 3 ：Calculate the value of the exponent to get $P(2)=\frac{1200}{1+9 * 0.201896517995}$

Step 4 ：Multiply inside the denominator to get $P(2)=\frac{1200}{1+1.81706866195}$

Step 5 ：Add inside the denominator to get $P(2)=\frac{1200}{2.81706866195}$

Step 6 ：Divide to find the population to get $P(2)=426.26$

Step 7 ：So, to the nearest whole number, the fish population after 2 years will be $\boxed{426}$