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Use a graphing calculator and the following scenario.
The population $P$ of a fish farm in $t$ years is modeled by the equation $P (t) = \frac{1200}{1 + 9 e^{- 0.8 t}}$ .

To the nearest whole number, what will the fish population be after 2 years?
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Answer

So, to the nearest whole number, the fish population after 2 years will be $426$

Steps

Step 1 ：Substitute $t = 2$ into the equation to get $P (2) = \frac{1200}{1 + 9 e^{- 0.8 * 2}}$

Step 2 ：Simplify the exponent to get $P (2) = \frac{1200}{1 + 9 e^{- 1.6}}$

Step 3 ：Calculate the value of the exponent to get $P (2) = \frac{1200}{1 + 9 * 0.201896517995}$

Step 4 ：Multiply inside the denominator to get $P (2) = \frac{1200}{1 + 1.81706866195}$

Step 5 ：Add inside the denominator to get $P (2) = \frac{1200}{2.81706866195}$

Step 6 ：Divide to find the population to get $P (2) = 426.26$

Step 7 ：So, to the nearest whole number, the fish population after 2 years will be $426$