Question 8, 2.3.67
Points: 0 of 1
Find an equation for the line with the given properties. Express your answer using either the general form or the slope-intercept form of the equation of a line.
Parallel to the line $y=4 x$; containing the point $(-4,3)$
The equation is $\square$.
(Type an equation. Simplify your answer.)
Answer
\(\boxed{y=4x+19}\) is the final answer.
Step 1 ：The given line is parallel to the line $y=4x$. This means that the slope of the line we are looking for is also 4.
Step 2 ：We are also given that the line contains the point $(-4,3)$. We can substitute this point into the equation $y=mx+b$ to find the y-intercept $b$.
Step 3 ：Substituting the point $(-4,3)$ into the equation $y=mx+b$ gives us $3=4*(-4)+b$.
Step 4 ：Solving this equation for $b$ gives us $b=19$.
Step 5 ：Therefore, the equation of the line in slope-intercept form is $y=4x+19$.
Step 6 ：\(\boxed{y=4x+19}\) is the final answer.
