Problem

Determine if the following equation has $x$-axis symmetry, $y$-axis symmetry, origin symmetry, or none of these.
\[
x+y^{2}=1
\]

Answer

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Answer

Final Answer: The equation \(x+y^{2}=1\) has \(\boxed{x\text{-axis symmetry}}\).

Steps

Step 1 :Determine if the following equation has x-axis symmetry, y-axis symmetry, origin symmetry, or none of these: \(x+y^{2}=1\)

Step 2 :To determine the symmetry of the equation, we need to perform the following tests:

Step 3 :For x-axis symmetry, replace y with -y in the equation. If the equation remains the same, it has x-axis symmetry.

Step 4 :For y-axis symmetry, replace x with -x in the equation. If the equation remains the same, it has y-axis symmetry.

Step 5 :For origin symmetry, replace x with -x and y with -y in the equation. If the equation remains the same, it has origin symmetry.

Step 6 :From the tests, we observe that the equation has x-axis symmetry but does not have y-axis symmetry or origin symmetry.

Step 7 :Final Answer: The equation \(x+y^{2}=1\) has \(\boxed{x\text{-axis symmetry}}\).

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