Solving a decimal word problem using a linear inequality with the variabl...
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A phone company offers two monthly charge plans. In Plan A, the customer pays a monthly fee of $\$ 26$ and then an additional 8 cents per minute of use. In Pla B, the customer pays a monthly fee of $\$ 25$ and then an additional 9 cents per minute of use.

For what amounts of monthly phone use will Plan A cost no more than Plan B? Use $m$ for the number of minutes of phone use, and solve your inequality for $m$.
\begin{tabular}{|ccc|}
\hline$\square< \square$ & $\square> \square$ & $\square \leq \square$ \\
$\square \geq \square$ & \\
$\times$ & 5 \\
\hline
\end{tabular}

Step 1 ：The problem is asking for the number of minutes of phone use where Plan A is cheaper or equal to Plan B. This can be represented as a linear inequality where the cost of Plan A is less than or equal to the cost of Plan B.

Step 2 ：The cost of Plan A can be represented as \(26 + 0.08m\) and the cost of Plan B can be represented as \(25 + 0.09m\).

Step 3 ：We need to find the value of \(m\) where \(26 + 0.08m \leq 25 + 0.09m\).

Step 4 ：Solving the equation, we find that \(m = 100\). This means that for 100 minutes of phone use, the cost of Plan A is equal to the cost of Plan B.

Step 5 ：However, we want to find the number of minutes for which Plan A is less than or equal to Plan B. Therefore, for any number of minutes less than or equal to 100, Plan A will be cheaper or equal in cost to Plan B.

Step 6 ：Final Answer: \(\boxed{m \leq 100}\)