Let $f(x)=-6 e^{x}+e^{2}$. Find $f^{\prime}(x)$
\[
f^{\prime}(x)=
\]

Answer

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Answer

$\boxed{f^{\prime}(x)=-6 e^{x}}$ is the derivative of the function $f(x)=-6 e^{x}+e^{2}$

Steps

Step 1 ：Given the function $f(x)=-6 e^{x}+e^{2}$

Step 2 ：Apply the power rule to find the derivative of $-6 e^{x}$, which is $-6 e^{x}$

Step 3 ：The derivative of $e^{2}$ is 0 because $e^{2}$ is a constant and the derivative of a constant is 0

Step 4 ：So, the derivative of the function $f(x)$ is $f^{\prime}(x)=-6 e^{x}+0$

Step 5 ：Simplify to get $f^{\prime}(x)=-6 e^{x}$

Step 6 ：$\boxed{f^{\prime}(x)=-6 e^{x}}$ is the derivative of the function $f(x)=-6 e^{x}+e^{2}$