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The data in the following table show the association between cigar smoking and death from cancer for 131,632 men. Note: current cigar smoker means cigar smoker at time of death.
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If an individual is randomly selected from this study, what is the probability that he died from cancer or was a current cigar smoker?
$\mathrm{P}$ (died from cancer or current cigar smoker)=
(Round to three decimal places as needed.)
table
\begin{tabular}{|lcc|}
\hline & \begin{tabular}{c}
Died from \\
Cancer
\end{tabular} & \begin{tabular}{c}
Did Not Die \\
from Cancer
\end{tabular} \\
\hline oked cigars & 542 & 115,593 \\
\hline igar smoker & 79 & 9,305 \\
\hline igar smoker & 163 & 5,950 \\
\hline
\end{tabular}
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Step 1 ：The question is asking for the probability that a randomly selected individual either died from cancer or was a current cigar smoker. This can be calculated by adding the number of individuals who died from cancer and the number of current cigar smokers, and then dividing by the total number of individuals. However, we need to be careful not to double count individuals who both died from cancer and were current cigar smokers.

Step 2 ：Let's denote the number of individuals who died from cancer as \(died\_from\_cancer\), the number of current cigar smokers as \(current\_smoker\), and the total number of individuals as \(total\).

Step 3 ：From the table, we have \(died\_from\_cancer = 784\), \(current\_smoker = 116135\), and \(total = 131632\).

Step 4 ：The probability can be calculated as \(probability = \frac{died\_from\_cancer + current\_smoker}{total}\).

Step 5 ：Substituting the values, we get \(probability = \frac{784 + 116135}{131632} = 0.888\).

Step 6 ：Final Answer: The probability that a randomly selected individual either died from cancer or was a current cigar smoker is \(\boxed{0.888}\).