Solve the problem involving probabilities with independent events.

A single die is rolled twice. Find the probability of getting a 2 the first time and a 6 the second time.
$\frac{1}{12}$
$\frac{1}{6}$
$\frac{1}{36}$
$\frac{1}{3}$

Answer

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Final Answer: The probability of rolling a 2 on the first roll and a 6 on the second roll is $\frac{1}{36}$ .

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Step 1 ：The problem involves two independent events: rolling a 2 on the first roll and rolling a 6 on the second roll. The probability of each event can be calculated separately and then multiplied together to find the overall probability.

Step 2 ：The probability of rolling a 2 on a six-sided die is $\frac{1}{6}$ , and the probability of rolling a 6 is also $\frac{1}{6}$ .

Step 3 ：Therefore, the overall probability is $\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}$ .

Step 4 ：Final Answer: The probability of rolling a 2 on the first roll and a 6 on the second roll is $\frac{1}{36}$ .

Solve the problem involving probabilities with independent events. A single die is rolled twice. Find the probability of getting a 2 the first time and a 6 the second time.1121613613

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Solve the problem involving probabilities with independent events.

A single die is rolled twice. Find the probability of getting a 2 the first time and a 6 the second time.
$\frac{1}{12}$
$\frac{1}{6}$
$\frac{1}{36}$
$\frac{1}{3}$