Find the equation of the line parallel to the line $3x-4y=12$ and passing through the point $(2,-3)$.

Step 1 ：Step 1: Find the slope of the given line. We know the general form of a linear equation is $y=mx+b$, where $m$ is the slope. So we need to convert the given equation into this form. We have $3x-4y=12$, so $y=\frac{3}{4}x-3$. Hence, the slope of the given line is $\frac{3}{4}$.

Step 2 ：Step 2: Since the line we are looking for is parallel to the given line, it will have the same slope, that is, $m=\frac{3}{4}$.

Step 3 ：Step 3: Substitute the slope and the given point $(2,-3)$ into the equation $y=mx+b$ to find the y-intercept $b$. We get $-3=\frac{3}{4}\ast 2+b$, which simplifies to $-3=\frac{3}{2}+b$. Solving for $b$, we get $b=-3-\frac{3}{2}=-\frac{9}{2}$.

Step 4 ：Step 4: Substitute the slope and y-intercept into the equation $y=mx+b$ to find the equation of the line. We get $y=\frac{3}{4}x-\frac{9}{2}$.