ind all real zeros of the function.
\[
g(x)=-2 x\left(x^{2}-9\right)\left(x^{2}+36\right)
\]

If there is more than one answer, separate them with commas.
\[
\text { zero(s): } \square
\]

Answer

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Answer

Final Answer: The real zeros of the function are \(\boxed{-3, 0, 3}\)

Steps

Step 1 ：Define the function \(g(x) = -2x(x^2 - 9)(x^2 + 36)\)

Step 2 ：Solve the equation \(g(x) = 0\) to find the zeros of the function

Step 3 ：The solutions are \(x = -3, 0, 3, -6i, 6i\)

Step 4 ：Filter out the real solutions, which are \(x = -3, 0, 3\)

Step 5 ：Final Answer: The real zeros of the function are \(\boxed{-3, 0, 3}\)