A ball is projected upward from the ground. Its distance in feet from the ground in $t$ seconds is given by $s(t)=-16 t^{2}+122 t$. At what times will the ball be 227 feet from the ground?

At $\square$ second(s), the ball will be 227 feet from the ground.

Step 1 ：The problem is asking for the time(s) when the ball will be 227 feet from the ground. This means we need to solve the equation \(s(t) = 227\) for \(t\).

Step 2 ：The equation is a quadratic equation, so we can use the quadratic formula to solve it. The quadratic formula is \(t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a\), \(b\), and \(c\) are the coefficients of the quadratic equation. In this case, \(a = -16\), \(b = 122\), and \(c = -227\).

Step 3 ：Substituting the values of \(a\), \(b\), and \(c\) into the quadratic formula, we get two times: approximately 3.22 seconds and 4.40 seconds. These are the times when the ball will be 227 feet from the ground.

Step 4 ：Final Answer: At \(\boxed{3.22}\) and \(\boxed{4.40}\) second(s), the ball will be 227 feet from the ground.