Problem

Find $f_{x x}, f_{x y}, f_{y x}$ and $f_{y y}$ for the following function. (Remember, $f_{y x}$ means to differentiate with respect to $y$ and then with respect to $x$.)
\[
f(x, y)=9 y \ln x
\]
\[
\mathrm{f}_{\mathrm{xox}}=\square
\]

Answer

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Answer

\(\boxed{f_{xx} = -\frac{9y}{x^2}, f_{xy} = \frac{9}{x}, f_{yx} = \frac{9}{x}, f_{yy} = 0}\)

Steps

Step 1 :First, we find the first order partial derivatives of the function \(f(x, y)=9y \ln x\).

Step 2 :We find that \(f_x = \frac{9y}{x}\) and \(f_y = 9\ln x\).

Step 3 :Next, we differentiate \(f_x\) with respect to \(x\) to get \(f_{xx}\), and we find that \(f_{xx} = -\frac{9y}{x^2}\).

Step 4 :We then differentiate \(f_x\) with respect to \(y\) to get \(f_{xy}\), and we find that \(f_{xy} = \frac{9}{x}\).

Step 5 :We differentiate \(f_y\) with respect to \(x\) to get \(f_{yx}\), and we find that \(f_{yx} = \frac{9}{x}\).

Step 6 :Finally, we differentiate \(f_y\) with respect to \(y\) to get \(f_{yy}\), and we find that \(f_{yy} = 0\).

Step 7 :\(\boxed{f_{xx} = -\frac{9y}{x^2}, f_{xy} = \frac{9}{x}, f_{yx} = \frac{9}{x}, f_{yy} = 0}\)

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