Solve the following system of equations with the substitution method:
$$\{\begin{array}{ll}-3x+12y& =-24\\ x& =4y+8\end{array}$$

Step 1 ：Understand the problem: We are given a system of two equations and we are asked to solve it using the substitution method.

Step 2 ：Start the solution: The substitution method involves solving one of the equations for one variable in terms of the other variable and then substituting this expression into the other equation.

Step 3 ：Solve one of the equations for one variable: The second equation is already solved for x, so we can use it as it is. We have: $x=4y+8$

Step 4 ：Substitute the expression for x into the other equation: Substitute $x=4y+8$ into the first equation: $-3(4y+8)+12y=-24$ which simplifies to $-12y-24+12y=-24$ and further simplifies to $-24=-24$

Step 5 ：Solve for y: The y terms cancel out, leaving $-24=-24$. This is a true statement, which means that the system of equations has infinitely many solutions.

Step 6 ：Check the solution: Since the y terms cancel out and we are left with a true statement, this means that any value of y will satisfy the first equation as long as $x=4y+8$.

Step 7 ：Write the final answer: The system of equations has infinitely many solutions, and any pair $(x,y)$ that satisfies $x=4y+8$ is a solution. So, the final answer is $\boxed{{\displaystyle \text{The system of equations has infinitely many solutions}}}$