$\frac{1}{3}+-\frac{7}{4}=$

Step 1 ：The problem is asking for the sum of two fractions, \(\frac{1}{3}\) and \(-\frac{7}{4}\).

Step 2 ：To solve this, we need to find a common denominator for the two fractions, which is the least common multiple of the denominators 3 and 4.

Step 3 ：Once we have the common denominator, we can convert each fraction to an equivalent fraction with the common denominator, and then add or subtract the numerators as indicated.

Step 4 ：The common denominator of 3 and 4 is 12. So, we convert the fractions to have this common denominator: \(\frac{1}{3} = \frac{4}{12}\) and \(-\frac{7}{4} = -\frac{21}{12}\).

Step 5 ：Now, we add the two fractions: \(\frac{4}{12} - \frac{21}{12} = -\frac{17}{12}\).

Step 6 ：So, the sum of \(\frac{1}{3}\) and \(-\frac{7}{4}\) is \(-\frac{17}{12}\).

Step 7 ：Final Answer: \(\boxed{-\frac{17}{12}}\)