Problem

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Use the data in the table below, which shows the employment status of individuals in a particular town by age group.
\begin{tabular}{|c|c|c|c|}
\hline Age & Full-time & Part-time & Unemployed \\
\hline $\mathbf{0 - 1 7}$ & 26 & 179 & 329 \\
\hline $\mathbf{1 8 - 2 5}$ & 315 & 200 & 301 \\
\hline $\mathbf{2 6 - 3 4}$ & 339 & 70 & 26 \\
\hline $\mathbf{3 5 - 4 9}$ & 456 & 191 & 266 \\
\hline $\mathbf{5 0 +}$ & 453 & 177 & 327 \\
\hline
\end{tabular}

If a person is randomly chosen from the town's population, what is the probability that the person is under 18 or employed part-time?
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Final Answer: The probability that a person is under 18 or employed part-time is approximately \(\boxed{0.321}\).

Steps

Step 1 :The question is asking for the probability that a person is either under 18 or employed part-time. To solve this, we need to calculate the total number of people under 18 and the total number of people employed part-time, and then divide by the total population.

Step 2 :First, let's calculate the total population. This is the sum of all the numbers in the table, which is 3655.

Step 3 :Next, let's calculate the number of people under 18. This is the sum of the numbers in the row for ages 0 - 17, which is 534.

Step 4 :Then, let's calculate the number of people employed part-time. This is the sum of the numbers in the column for part-time employment, which is 817.

Step 5 :Finally, we subtract the number of people who are both under 18 and employed part-time (since we counted them twice), which is 179, and divide by the total population to get the probability.

Step 6 :The calculation is as follows: \(\frac{534 + 817 - 179}{3655} = 0.320656634746922\)

Step 7 :Final Answer: The probability that a person is under 18 or employed part-time is approximately \(\boxed{0.321}\).

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