Problem

Complete the table.
\begin{tabular}{|c|c|}
\hline \multicolumn{2}{|c|}{$f(x)=2 x-3$} \\
\hline$x$ & $f(x)$ \\
\hline 3 & $\square$ \\
\hline 4 & $\square$ \\
\hline 5 & $\square$ \\
\hline 6 & $\square$ \\
\hline
\end{tabular}
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Answer

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Answer

The completed table is: \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{\(f(x)=2 x-3\)} \\ \hline\(x\) & \(f(x)\) \\ \hline 3 & \(\boxed{3}\) \\ \hline 4 & \(\boxed{5}\) \\ \hline 5 & \(\boxed{7}\) \\ \hline 6 & \(\boxed{9}\) \\ \hline \end{tabular}

Steps

Step 1 :The question asks to complete the table for the function \(f(x)=2x-3\). This means we need to substitute the given \(x\) values into the function and calculate the corresponding \(f(x)\) values.

Step 2 :For \(x=3\), \(f(x)=2(3)-3=3\)

Step 3 :For \(x=4\), \(f(x)=2(4)-3=5\)

Step 4 :For \(x=5\), \(f(x)=2(5)-3=7\)

Step 5 :For \(x=6\), \(f(x)=2(6)-3=9\)

Step 6 :The completed table is: \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{\(f(x)=2 x-3\)} \\ \hline\(x\) & \(f(x)\) \\ \hline 3 & \(\boxed{3}\) \\ \hline 4 & \(\boxed{5}\) \\ \hline 5 & \(\boxed{7}\) \\ \hline 6 & \(\boxed{9}\) \\ \hline \end{tabular}

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