Solve for $z$.
Assume the equation has a solution for $z$.
\[
\begin{array}{l}
16 z+29 z=p z-v \\
z=\square
\end{array}
\]
The solution to the equation is \(z = \boxed{\frac{v}{p-45}}\).
Step 1 :Assume the equation has a solution for z: \(16z + 29z = pz - v\).
Step 2 :Combine like terms on the left side of the equation to get \(45z = pz - v\).
Step 3 :Isolate z on one side of the equation to solve for z.
Step 4 :The solution to the equation is \(z = \boxed{\frac{v}{p-45}}\).