Question 6

If $\log _{2}(4 x+2)=5$, then $x=$ You may enter the exact value or round to 4 decimal places

Solve for x

Answer

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Answer

The solution to the equation $\log _{2}(4 x+2)=5$ is $x = \boxed{\frac{15}{2}}$ or $x = \boxed{7.5}$ when rounded to one decimal place.

Steps

Step 1 ：Convert the logarithmic equation into an exponential equation. The base of the logarithm becomes the base of the power, the right side of the equation becomes the exponent, and the argument of the logarithm becomes the result.

Step 2 ：Solve for x by isolating it on one side of the equation.

Step 3 ：The solution to the equation $\log _{2}(4 x+2)=5$ is $x = \boxed{\frac{15}{2}}$ or $x = \boxed{7.5}$ when rounded to one decimal place.

Question 6 If $\log _{2}(4 x+2)=5$, then $x=$ You may enter the exact value or round to 4 decimal places Solve for x

Answer

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Question 6

If $\log _{2}(4 x+2)=5$, then $x=$ You may enter the exact value or round to 4 decimal places

Solve for x