Problem

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Test the claim below about the mean of the differences for a population of paired data at the level of significance $\alpha$. Assume the samples are random and dependent, and the populations are normally distributed.

Claim: $\mu_{d} \geq 0 ; \alpha=0.10$. Sample statistics: $\bar{d}=-2.2, s_{d}=1.2, n=16$

Identify the null and alternative hypotheses. Choose the correct answer below.
A.
\[
\begin{array}{l}
H_{0}: \mu_{d}=0 \\
H_{a}: \mu_{d} \neq 0
\end{array}
\]
C.
\[
\begin{array}{l}
H_{0}: \mu_{d} \leq 0 \\
H_{a}: \mu_{d}> 0
\end{array}
\]
E.
\[
\begin{array}{l}
H_{0}: \mu_{d} \geq 0 \\
H_{a}: \mu_{d}< 0
\end{array}
\]
B.
\[
\begin{array}{l}
H_{0}: \mu_{d} \neq 0 \\
H_{a}: \mu_{d}=0
\end{array}
\]
D.
\[
\begin{array}{l}
H_{0}: \mu_{d}< 0 \\
H_{a}: \mu_{d} \geq 0
\end{array}
\]
F.
\[
\begin{array}{l}
H_{0}: \mu_{d}> 0 \\
H_{a}: \mu_{d} \leq 0
\end{array}
\]

The test statistic is $\mathrm{t}=\square$.
(Round to two decimal places as needed.)
The P-value is $\square$.
(Round to three decimal places as needed.)
Since the $\mathrm{P}$-value is the level of significance, the null hypothesis. There statistically significant evidence to reject the claim.

Answer

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Answer

\(\boxed{\text{There is statistically significant evidence to reject the claim that } \mu_{d} \geq 0}\)

Steps

Step 1 :The null hypothesis (H0) is \(\mu_{d} \geq 0\) and the alternative hypothesis (Ha) is \(\mu_{d} < 0\)

Step 2 :Calculate the test statistic using the formula: t = (\(\bar{d}\) - \(\mu_{d}\)) / (s\(_{d}\) / \(\sqrt{n}\))

Step 3 :Substitute the given values into the formula: t = (-2.2 - 0) / (1.2 / \(\sqrt{16}\)) = -7.33

Step 4 :The test statistic t = -7.33

Step 5 :Calculate the P-value. The P-value is the probability of obtaining a result as extreme as the observed data, assuming the null hypothesis is true

Step 6 :Since we are dealing with a one-tailed test (because Ha: \(\mu_{d} < 0\)), we look up the P-value in a t-distribution table for t = -7.33 and df = n - 1 = 16 - 1 = 15

Step 7 :The t-value is so extreme that it's off the charts, and the P-value is less than 0.001

Step 8 :So, the P-value < 0.001

Step 9 :Since the P-value is less than the level of significance (0.10), we reject the null hypothesis

Step 10 :\(\boxed{\text{There is statistically significant evidence to reject the claim that } \mu_{d} \geq 0}\)

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