Water flows into an empty reservoir at a rate of $3400 + 15 t$ gal/hour. What is the quantity of water in the reservoir after 10 hours?

Answer: gallons.

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Final Answer: The quantity of water in the reservoir after 10 hours is $34750$ gallons.

Steps

Step 1 ：The rate at which water is flowing into the reservoir is given by the function $3400 + 15 t$ .

Step 2 ：To find the total quantity of water after 10 hours, we need to integrate this function from 0 to 10.

Step 3 ：The result of the integration is 34750.

Step 4 ：This means that after 10 hours, there will be 34750 gallons of water in the reservoir.

Step 5 ：Final Answer: The quantity of water in the reservoir after 10 hours is $34750$ gallons.