Given $f(w)=-w^{3}+13$, find the following:
a) $w$-intercept(s) $=$
b) $f(w)$-intercept $=$
Substitute $w=0$ into the function to find the $f(w)$-intercept. So, $f(0)=-0^{3}+13=13$. Therefore, the $f(w)$-intercept is $\boxed{13}$.
Step 1 :Set the function $f(w)$ equal to zero and solve for $w$ to find the $w$-intercept(s). So, $-w^{3}+13=0$.
Step 2 :Rearrange the equation to get $w^{3}=13$.
Step 3 :Take the cube root of both sides to find $w=\sqrt[3]{13}$. So, the $w$-intercept is $\boxed{\sqrt[3]{13}}$.
Step 4 :Substitute $w=0$ into the function to find the $f(w)$-intercept. So, $f(0)=-0^{3}+13=13$. Therefore, the $f(w)$-intercept is $\boxed{13}$.