Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $\mathrm{\$}24,000$ and the standard deviation is $\mathrm{\$}1000$.

Use the 68-95-99.7 Rule to find the percentage of buyers who paid more than $\mathrm{\$}27,000$.
Price of a Model of a New Car (Thousands)

The percentage of buyers who paid more than $\mathrm{\$}27,000$ is $\mathrm{\%}$.

Step 1 ：The problem is asking for the percentage of buyers who paid more than $27,000foraparticularmodelofanewcar.Thepricespaidforthiscarfollowanormaldistributionwithameanof$24,000 and a standard deviation of $1,000.

Step 2 ：The 68-95-99.7 rule, also known as the empirical rule, states that for a normal distribution, almost all values lie within 3 standard deviations of the mean. More specifically, 68% of the data falls within the first standard deviation from the mean, 95% fall within two standard deviations, and 99.7% fall within three standard deviations.

Step 3 ：In this case, a price of $27,000 is 3 standard deviations above the mean. According to the empirical rule, 99.7% of the data falls within three standard deviations of the mean.

Step 4 ：This means that the percentage of buyers who paid more than $27,000, which is more than 3 standard deviations above the mean, is 100% - 99.7% = 0.3%.

Step 5 ：Final Answer: The percentage of buyers who paid more than $27,000 is $\boxed{{\displaystyle 0.3\mathrm{\%}}}$.