Find the sum of the infinite geometric series: (3, 6, 12, 24, ...)

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Step:1 ：First, we need to identify the common ratio of the geometric series. We do this by dividing the second term by the first term, and we find that the common ratio (r = frac{6}{3} = 2)Step:2 ：Next, we use the formula for the sum of an infinite geometric series, which is (S = frac{a}{1 - r}), where (a) is the first term and (r) is the common ratio.Step:3 ：Substituting the given values into the formula, we have (S = frac{3}{1 - 2})

Answer

Step: 1 ：First, we need to identify the common ratio of the geometric series. We do this by dividing the second term by the first term, and we find that the common ratio (r = frac{6}{3} = 2)Step: 2 ：Next, we use the formula for the sum of an infinite geometric series, which is (S = frac{a}{1 - r}), where (a) is the first term and (r) is the common ratio.Step: 3 ：Substituting the given values into the formula, we have (S = frac{3}{1 - 2})

Find the sum of the infinite geometric series: \(3, 6, 12, 24, ...\)

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