It is estimated that $93 \%$ of senior citizens suffer from sleep disorders and $8 \%$ suffer from anxiety. Moreover, $5 \%$ of senior citizens suffer from both sleep disorders and anxiety.

Answer the questions below. (If necessary, consult a list of formulas.)
(a) Find the probability that a senior citizen suffers from anxiety, given that he or she has sleep disorder. Round your answer to 2 decimal places.
(b) Given that a senior citizen suffers from anxiety, what is the probability that he or she also suffers from sleep disorder? Round your answer to 2 decimal places.

Step 1 ：Given that the probability of a senior citizen suffering from both sleep disorders and anxiety, denoted as \(P(A \cap B)\), is 0.05.

Step 2 ：The probability of a senior citizen suffering from sleep disorders, denoted as \(P(B1)\), is 0.93.

Step 3 ：The probability of a senior citizen suffering from anxiety, denoted as \(P(B2)\), is 0.08.

Step 4 ：We can calculate the conditional probability of a senior citizen suffering from anxiety given that he or she has sleep disorder, denoted as \(P(A|B1)\), using the formula \(P(A|B1) = \frac{P(A \cap B)}{P(B1)}\). Substituting the given values, we get \(P(A|B1) = \frac{0.05}{0.93}\).

Step 5 ：Rounding to 2 decimal places, we get \(P(A|B1) = \boxed{0.05}\).

Step 6 ：Similarly, we can calculate the conditional probability of a senior citizen suffering from sleep disorder given that he or she has anxiety, denoted as \(P(A|B2)\), using the formula \(P(A|B2) = \frac{P(A \cap B)}{P(B2)}\). Substituting the given values, we get \(P(A|B2) = \frac{0.05}{0.08}\).

Step 7 ：Rounding to 2 decimal places, we get \(P(A|B2) = \boxed{0.62}\).