Find all solutions of the equation $2 \cos x-1=0$.
The answer is $A+B k \pi$ and $C+D k \pi$ where $k$ is any integer, $0< A< C< 2 \pi$,
\[
\begin{array}{l}
A=\square, B=\square, D=\square \\
C=\square
\end{array}
\]

Step 1 ：Given the equation \(2 \cos x - 1 = 0\).

Step 2 ：Rewrite the equation as \(\cos x = \frac{1}{2}\).

Step 3 ：The solutions to this equation are \(x = \frac{\pi}{3} + 2k\pi\) and \(x = -\frac{\pi}{3} + 2k\pi\) where \(k\) is any integer.

Step 4 ：So, \(A = \frac{\pi}{3}\), \(B = 2\), \(C = -\frac{\pi}{3}\), and \(D = 2\).

Step 5 ：The solutions to the equation are \(x = A + Bk\pi\) and \(x = C + Dk\pi\) where \(k\) is any integer, \(0

Step 6 ：The values are \(A = \boxed{1.04719755119660}\), \(B = \boxed{2}\), \(C = \boxed{5.23598775598299}\), and \(D = \boxed{2}\).