Find the domain of the function (f(x) = frac{1}{sqrt{x^2 - 9}})

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Step:1 ：To find the domain of the function, we first look at the denominator (sqrt{x^2 - 9}). We know that the value under the square root must be greater than or equal to 0. So, (x^2 - 9 geq 0)Step:2 ：Solving the inequality gives us two possibilities: [x leq -3] or [x geq 3]Step:3 ：However, because we&#x27;re dealing with a rational function, we need to ensure that the denominator is not equal to 0. So the domain of the function is (x < -3) or (x > 3)

Answer

Step: 1 ：To find the domain of the function, we first look at the denominator (sqrt{x^2 - 9}). We know that the value under the square root must be greater than or equal to 0. So, (x^2 - 9 geq 0)Step: 2 ：Solving the inequality gives us two possibilities: [x leq -3] or [x geq 3]Step: 3 ：However, because we&#x27;re dealing with a rational function, we need to ensure that the denominator is not equal to 0. So the domain of the function is (x < -3) or (x > 3)

Find the domain of the function \(f(x) = \frac{1}{\sqrt{x^2 - 9}}\)

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