Let \( z = 1 + i \sqrt{3} \). Compute \( \frac{z}{1 - z} \) and simplify the result.
Finally, simplifying the complex numbers in the denominator, we have: \( \frac{1 - i \sqrt{3}}{i \sqrt{2}} \)
Step 1 :Firstly, we notice that the denominator in the expression is a complex number, so we can't directly compute the division. We need to rationalize the denominator using complex conjugates. The complex conjugate of a complex number \( a + bi \) is \( a - bi \).
Step 2 :For \( z = 1 + i \sqrt{3} \), the complex conjugate is \( 1 - i \sqrt{3} \).
Step 3 :We multiply both the numerator and the denominator by the complex conjugate to get: \( \frac{z}{1 - z} \times \frac{1 - i \sqrt{3}}{1 - i \sqrt{3}} = \frac{(1 + i \sqrt{3})(1 - i \sqrt{3})}{(1 - (1 + i \sqrt{3}))(1 - i \sqrt{3})} \)
Step 4 :Simplify the expressions in the numerator and the denominator to get: \( \frac{1 - 3 + 2i \sqrt{3}}{- i \sqrt{3}} \)
Step 5 :Simplify further to get: \( \frac{-2 + 2i \sqrt{3}}{- i \sqrt{3}} \)
Step 6 :Divide the numerator and the denominator by \( -2 \) to get: \( \frac{1 - i \sqrt{3}}{i \sqrt{3/2}} \)
Step 7 :Finally, simplifying the complex numbers in the denominator, we have: \( \frac{1 - i \sqrt{3}}{i \sqrt{2}} \)