Solve for $x$.
\[
16^{6 x}=11^{-x-3}
\]
Write the exact answer using either base-10 or base- $e$ logarithms.
\[
x=\square
\]
$\square \log \square$
$\square \ln \square$
No
solution
$x$
5
\(\boxed{x = -\frac{3 \log 11}{\log 184549376}}\) is the solution to the equation.
Step 1 :The given equation is in the form of \(a^{bx} = c^{dx}\), which can be solved by taking the logarithm on both sides. This will allow us to bring down the exponents and solve for \(x\).
Step 2 :Taking the logarithm of both sides of the equation \(16^{6x} = 11^{-x - 3}\) gives us the equation \(x = -\frac{3 \log 11}{\log 184549376}\).
Step 3 :\(\boxed{x = -\frac{3 \log 11}{\log 184549376}}\) is the solution to the equation.