Question 7 - 1 fort
Abal is thrown vertocaly in the air with a velocity of $95 \mathrm{ft} / \mathrm{s}$. Use the projectile formula $h=-16 t^{2}+t, t \mathrm{to} d e t e r m i n e$ at what timess in secunds; the ball is at a height of $120 \mathrm{ft}$. Round your answer(s) to the nearest tenth of a second.

Provide your arsiver belon:

Step 1 ：The problem is asking for the time at which the ball reaches a height of 120 feet. We can use the given formula for the height of a projectile, which is \(h=-16t^2+v_0t\), where \(h\) is the height, \(t\) is the time, and \(v_0\) is the initial velocity. In this case, \(v_0\) is given as 95 ft/s. We can set \(h\) to 120 ft and solve for \(t\).

Step 2 ：Substitute the given values into the equation: \(-16t^2 + 95t - 120 = 0\).

Step 3 ：Solving this equation gives us the times at which the ball is at a height of 120 feet.

Step 4 ：The solutions to the equation are \(t = 1.8\) seconds and \(t = 4.1\) seconds.

Step 5 ：Final Answer: The ball is at a height of 120 feet at times \(t = \boxed{1.8}\) seconds and \(t = \boxed{4.1}\) seconds.