Use logarithms to find the $x$-intercept of the graph of the given function.
\[
y=11-9^{(x+1)}
\]
The $x$-intercept occurs at $x=\square$. (Round to two decimal places as needed.)

Answer

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Answer

$\boxed{x=0.09}$

Steps

Step 1 ：The x-intercept of a function is the point where the function crosses the x-axis. At this point, the y-coordinate is 0. So, we need to solve the equation $11 - 9^{(x+1)} = 0$ for x.

Step 2 ：Solving for x, we get $x = 0.09$.

Step 3 ：$\boxed{x=0.09}$

Use logarithms to find the $x$-intercept of the graph of the given function.\[y=11-9^{(x+1)}\]The $x$-intercept occurs at $x=\square$. (Round to two decimal places as needed.)

Answer

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Use logarithms to find the $x$-intercept of the graph of the given function.
\[
y=11-9^{(x+1)}
\]
The $x$-intercept occurs at $x=\square$. (Round to two decimal places as needed.)