Watch on Voutube
Try it!!
Given the function $f(x)=6 x^{2}-4 x+3$. Calculate the following values using synthetic division and th Remainder Theorem:
\[
\begin{array}{l}
f(-2)= \\
f(-1)= \\
f(0)= \\
f(1)= \\
f(2)=
\end{array}
\]
Question Help: $\square$ Message instructor
Submit Question
Answer
The values of the function \(f(x)=6 x^{2}-4 x+3\) at \(x=-2, -1, 0, 1, 2\) are \(\boxed{35, 13, 3, 5, 19}\) respectively.
Step 1 ：The question is asking to calculate the value of the function \(f(x)=6 x^{2}-4 x+3\) at \(x=-2, -1, 0, 1, 2\). We can directly substitute these values into the function to get the result. We don't need to use synthetic division or the Remainder Theorem in this case because we are not trying to divide the polynomial or find the remainder of a division.
Step 2 ：Substitute the values \(-2, -1, 0, 1, 2\) into the function \(f(x)=6 x^{2}-4 x+3\).
Step 3 ：The values of the function \(f(x)=6 x^{2}-4 x+3\) at \(x=-2, -1, 0, 1, 2\) are \(\boxed{35, 13, 3, 5, 19}\) respectively.
