Find the expanded form of the ellipse with a center at the origin, a horizontal axis length of 10 and a vertical axis length of 6.

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Step:1 ：Given that the center of the ellipse is at the origin, its equation will be of the form (frac{x^2}{a^2} + frac{y^2}{b^2} = 1), where a is half of the horizontal axis length and b is half of the vertical axis length.Step:2 ：We are given that the horizontal axis length is 10, so (a = frac{10}{2} = 5).Step:3 ：Similarly, the vertical axis length is 6, so (b = frac{6}{2} = 3).Step:4 ：Substituting these values into the equation of the ellipse, we get the expanded form: (frac{x^2}{5^2} + frac{y^2}{3^2} = 1)

Answer

Step: 1 ：Given that the center of the ellipse is at the origin, its equation will be of the form (frac{x^2}{a^2} + frac{y^2}{b^2} = 1), where a is half of the horizontal axis length and b is half of the vertical axis length.Step: 2 ：We are given that the horizontal axis length is 10, so (a = frac{10}{2} = 5).Step: 3 ：Similarly, the vertical axis length is 6, so (b = frac{6}{2} = 3).Step: 4 ：Substituting these values into the equation of the ellipse, we get the expanded form: (frac{x^2}{5^2} + frac{y^2}{3^2} = 1)

Find the expanded form of the ellipse with a center at the origin, a horizontal axis length of 10 and a vertical axis length of 6.

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