Factor the binomial completely.
\[
x^{2}-\frac{1}{25}
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. $x^{2}-\frac{1}{25}=\square$ (Factor completely. Simplify your answer. Use integers or fractions for any numbers in the expression.
B. The polynomial is prime.
Final Answer: \(\boxed{(x - \frac{1}{5})(x + \frac{1}{5})}\)
Step 1 :Given expression is \(x^{2} - \frac{1}{25}\)
Step 2 :This is a difference of squares, which follows the pattern \(a^{2} - b^{2} = (a - b)(a + b)\)
Step 3 :In this case, \(a = x\) and \(b = \frac{1}{5}\) (since \((\frac{1}{5})^{2} = \frac{1}{25}\))
Step 4 :So, we can factor the expression as follows: \(x^{2} - \frac{1}{25} = (x - \frac{1}{5})(x + \frac{1}{5})\)
Step 5 :So, the correct choice is A. \(x^{2} - \frac{1}{25} = (x - \frac{1}{5})(x + \frac{1}{5})\)
Step 6 :Final Answer: \(\boxed{(x - \frac{1}{5})(x + \frac{1}{5})}\)