Problem

Calculate the minimum or maximum value of the function:
$f(x)=2 x+x^{2}-2$

Answer

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Answer

Final Answer: The minimum value of the function \(f(x)=2 x+x^{2}-2\) is \(\boxed{-3}\).

Steps

Step 1 :The function given is a quadratic function, which is in the form \(f(x) = ax^2 + bx + c\).

Step 2 :The maximum or minimum value of a quadratic function is found at its vertex.

Step 3 :The x-coordinate of the vertex can be calculated using the formula \(-b/2a\). In this case, \(a = 1\) and \(b = 2\), so the x-coordinate of the vertex is \(-2/(2*1) = -1\).

Step 4 :We can find the y-coordinate of the vertex, which is the minimum or maximum value of the function, by substituting \(x = -1\) into the function.

Step 5 :Substituting \(x = -1\) into the function gives us a y-coordinate of \(-3\).

Step 6 :Final Answer: The minimum value of the function \(f(x)=2 x+x^{2}-2\) is \(\boxed{-3}\).

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