The following are distances (in miles) traveled to the workplace by 5 employees of a certain brokerage firm.
$7.18, 24, 3, 18$

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Find the thindart devitition of this sampie of distances. Round your answer to two decimal places

Answer

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Answer

The standard deviation of the sample of distances is $8.36$ miles.

Steps

Step 1 ：Given distances are $7.18, 24, 3, 18$ .

Step 2 ：Calculate the mean (average) of the distances. The mean is $13.045$ .

Step 3 ：Subtract the mean from each distance and square the result. The squared differences are $34.398225000000004, 120.01202500000001, 100.902025, 24.552025$ .

Step 4 ：Find the mean of these squared differences. The mean of the squared differences is $69.966075$ .

Step 5 ：Take the square root of the mean of the squared differences to find the standard deviation. The standard deviation is $8.36$ .

Step 6 ：The standard deviation of the sample of distances is $8.36$ miles.

The following are distances (in miles) traveled to the workplace by 5 employees of a certain brokerage firm.7.18,24,3,18 Send data to caiculaterFind the thindart devitition of this sampie of distances. Round your answer to two decimal places

Answer

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The following are distances (in miles) traveled to the workplace by 5 employees of a certain brokerage firm.
$7.18, 24, 3, 18$

Send data to caiculater
Find the thindart devitition of this sampie of distances. Round your answer to two decimal places