Part 1 of 2
Points: 0 of 1
Drive-thru Restaurant $\mathrm{O}$
\begin{tabular}{|l|c|c|c|c|}
\hline & A & B & C & D \\
\hline Order Accurate & 328 & 266 & 237 & 148 \\
\hline Order Not Accurate & 38 & 60 & 31 & 20 \\
\hline
\end{tabular}
Restaurant $C$ disjoint events?

The probability of getting an order from Restaurant $\mathrm{C}$ or an order that is not accurate is $\square$.
(Round to three decimal places as needed.)

Step 1 ：Calculate the total number of orders: \(328 + 266 + 237 + 148 + 38 + 60 + 31 + 20 = 1128\)

Step 2 ：Calculate the number of orders from Restaurant C: \(237 + 31 = 268\)

Step 3 ：Calculate the number of orders that are not accurate: \(38 + 60 + 31 + 20 = 149\)

Step 4 ：Calculate the probability of getting an order from Restaurant C: \(268 / 1128 = 0.238\)

Step 5 ：Calculate the probability of getting an order that is not accurate: \(149 / 1128 = 0.132\)

Step 6 ：Calculate the number of orders from Restaurant C that are not accurate: \(31\)

Step 7 ：Calculate the probability of getting an order from Restaurant C that is not accurate: \(31 / 1128 = 0.027\)

Step 8 ：Calculate the probability of getting an order from Restaurant C or an order that is not accurate: \(0.238 + 0.132 - 0.027 = 0.343\)

Step 9 ：Final Answer: The probability of getting an order from Restaurant C or an order that is not accurate is \(\boxed{0.343}\)