Question 11
If $\ln x+\ln (x-5)=\ln (3 x)$, then $x=$
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\(\boxed{x = 8}\)
Step 1 :\(\ln [x(x-5)] = \ln (3x)\)
Step 2 :\(x(x-5) = 3x\)
Step 3 :\(x^2 - 5x = 3x\)
Step 4 :\(x^2 - 8x = 0\)
Step 5 :\(x(x - 8) = 0\)
Step 6 :\(x = 0\) or \(x = 8\)
Step 7 :Substitute \(x = 0\) back into the original equation, it does not satisfy the equation because the natural logarithm is undefined for zero.
Step 8 :\(\boxed{x = 8}\)